THE BEST 100% FREE 1Z0-071–100% FREE TEST ANSWERS | 1Z0-071 TEST STUDY GUIDE

The Best 100% Free 1z0-071–100% Free Test Answers | 1z0-071 Test Study Guide

The Best 100% Free 1z0-071–100% Free Test Answers | 1z0-071 Test Study Guide

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Oracle Database SQL Sample Questions (Q270-Q275):

NEW QUESTION # 270
Which three statements are true regarding the data types? (Choose three.)

  • A. The BLOBdata type column is used to store binary data in an operating system file.
  • B. The minimum column width that can be specified for a VARCHAR2data type column is one.
  • C. A TIMESTAMPdata type column stores only time values with fractional seconds.
  • D. Only one LONGcolumn can be used per table.
  • E. The value for a CHARdata type column is blank-padded to the maximum defined column width.

Answer: B,D,E


NEW QUESTION # 271
Examine these statements which execute successfully:

Both statements display departments ordered by their average salaries.
Which two are true?

  • A. Only the second statement will display departments with no employees.
  • B. Only the first statement will display departments with no employees.
  • C. Only the second statement will execute successfully if you add E.AVG_SAL to the select list.
  • D. Both statements will display departments with no employees.
  • E. Only the first statement will execute successfully if you add E.AVG_SAK to the select list.
  • F. Both statements will execute successfully If you add e.avg_sal to the select list.

Answer: A,F

Explanation:
A . Only the second statement will display departments with no employees. This is true because the second statement uses a LEFT JOIN to include all departments from the departments table, even those without matching entries in the employees table. When there are no employees in a department, the AVG(salary) will be NULL, and the department will still be displayed1.
C . Both statements will execute successfully if you add e.avg_sal to the select list. This is correct. Both statements calculate e.avg_sal as an average salary, either through a subquery or a join operation. Adding e.avg_sal to the select list will display the average salary alongside the departments. However, it's important to note that the first statement will not display departments with no employees because it does not use a join that would allow for NULL values from the employees table2.
Reference:
Understanding SQL JOINs - Stack Overflow1.
Oracle Documentation on JOIN Operations2.
Note: The other options are incorrect because:
B . The first statement will not display departments with no employees since it does not use a join that includes departments without matching employee records.
D . As explained, the first statement will not display departments with no employees.
E . There is a typo in the option; it should be E.AVG_SAL. Even if corrected, the first statement alone would not execute successfully because it does not include a join to bring in the avg_sal value.
F . The second statement will display departments with no employees, but the first statement will not, so this option is incorrect.


NEW QUESTION # 272
View the Exhibit and examine the structure of the PRODUCT_INFORMATIONand INVENTORIEStables.

You have a requirement from the supplies department to give a list containing PRODUCT_ID, SUPPLIER_ID, and QUANTITY_ON_HANDfor all the products wherein QUANTITY_ON_HANDis less than five.
Which two SQL statements can accomplish the task? (Choose two.)
SELECT i.product_id, i.quantity_on_hand, pi.supplier_id

  • A. FROM product_information
    NATURAL JOIN inventories AND quantity_on_hand < 5;
    SELECT i.product_id, i.quantity_on_hand, pi.supplier_id
  • B. FROM product_information pi JOIN inventories i
    ON (pi.product_id=i.product_id) AND quantity_on_hand < 5;
    SELECT i.product_id, i.quantity_on_hand, pi.supplier_id
  • C. FROM product_information pi JOIN inventories i
    USING (product_id) AND quantity_on_hand < 5;
  • D. FROM product_information pi JOIN inventories i
    ON (pi.product_id=i.product_id)
    WHERE quantity_on_hand < 5;
    SELECT product_id, quantity_on_hand, supplier_id

Answer: B,D


NEW QUESTION # 273
Which three are true about granting object privileges on tables, views, and sequences?

  • A. INSERT can be granted on tables, views, and sequences.
  • B. REFERENCES can be granted only on tables and views.
  • C. DELETE can be granted on tables, views, and sequences.
  • D. ALTER can be granted only on tables and sequences.
  • E. UPDATE can be granted only on tables and views.
  • F. SELECT can be granted only on tables and views.

Answer: B,D,F

Explanation:
In Oracle Database, object privileges are rights to perform a particular action on a specific object in the database. Here's why the other options are incorrect:
A). UPDATE can be granted on tables, views, and materialized views, but not sequences. B. DELETE cannot be granted on sequences because sequences do not store data that can be deleted. D. INSERT cannot be granted on sequences; sequences are used to generate numbers, not to be inserted into directly. C.
REFERENCES allows the grantee to create a foreign key that references the table or the columns of the table.
It is applicable only to tables and views. E. SELECT can indeed only be granted on tables and views (including materialized views). F. ALTER is an object privilege that can be granted on tables and sequences but not views.
For more details, one may refer to the Oracle Database SQL Language Reference documentation, which specifies the types of object privileges and the objects they apply to.


NEW QUESTION # 274
Examine these statements:
CREATE TABLE dept (
deptno NUMBER PRIMARY KEY,
diname VARCHAR2(10) ,
mgr NUMBER ,
CONSTRAINT dept_fkey FOREIGN KEY(mgr) REFERENCES emp (empno));
CREATE TABLE emp (
Empno NUMBER PRIMARY KEY,
Ename VARCHAR2 (10) ,
deptno NUMBER,
CONSTRAINT emp_fkey FOREIGN KEY (deptno) REFERENCES dept (deptno) DISABLE); ALTER TABLE emp MODIFY CONSTRAINT emp_fkey ENABLE; Which two are true?

  • A. The MGR column in the DEPT table will not be able to contain NULL values.
  • B. All three statements execute successfully in the order shown
  • C. The DEFT FKEY constraint definition must be removed from the CREATE TABLE DEF statement.and be added with an AITER TABLE statement once both tables are created, for the two CREATE TABLE statements to execute successfully in the order shown.
  • D. Both foreign key constraint definitions must be removed from the CREATE TABLE statements, andbe added with ALTER TABLE statements once both tables are created, for the two CREATE TABLEstatements to execute successfully in the order shown.
  • E. The CREATE TABLE EMP statement must precede the CREATE TABLE DEPT statement for all threestatements to execute successfully.
  • F. The Deptno column in the emp table will be able to contain nulls values.

Answer: B,F

Explanation:
E). True. The deptno column in the emp table can contain null values unless explicitly constrained not to, which is not the case here.
F). True. The three statements can execute successfully in the order shown. The foreign key constraint in the dept table is referring to the emp table which does not yet exist, but this is not a problem because it is not immediately enabled. The emp table is created next with a disabled foreign key constraint referencing the already created dept table. Finally, the foreign key constraint on emp is enabled after both tables are in place.
A is incorrect because the MGR column can contain NULL values as there is no NOT NULL constraint applied to it. B is incorrect because the CREATE TABLE EMP statement contains a disabled foreign key, so it can be created before CREATE TABLE DEPT. C and D are incorrect because foreign key constraints do not need to be removed and added later for the tables to be created successfully; they can be managed as shown in the provided statements.


NEW QUESTION # 275
......

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